C(x)=x^2+4x+8

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Solution for C(x)=x^2+4x+8 equation: 



(C)=C^2+4C+8

We move all terms to the left:

(C)-(C^2+4C+8)=0

We get rid of parentheses

-C^2+C-4C-8=0

We add all the numbers together, and all the variables

-1C^2-3C-8=0

a = -1; b = -3; c = -8;
Δ = b2-4ac
Δ = -32-4·(-1)·(-8)
Δ = -23
Delta is less than zero, so there is no solution for the equation

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